ON
Algorithms (3)
R' 2U 2R' 2U' R 2U 2R 2U'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
R 2B U 2F' U' 2B' U 2F U' R'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
R 2B 3Dw 2R' 3Dw' 2B' 3Dw 2R 3Dw' R'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R U 2F' U' 2B U 2F U' 2B' R'. Every algorithm above was run by our logic engine from that state and reaches "solved".