NO
Algorithms (3)
2U 2R' 2U' R' 2U 2R 2U' R
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
R U 2F' U' 2B U 2F U' 2B' R'
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
R2 2D 2R 2D' R' 2D 2R' 2D' R'
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R 2B U 2F' U' 2B' U 2F U' R'. Every algorithm above was run by our logic engine from that state and reaches "solved".