NL
Algorithms (3)
2L2 2U' 2L U2 2L' 2U 2L U2 2L
My choice
16 HTM · 9 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
R2 2D' 2L' U2 2L 2D 2L' U2 2L R2
16 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
F2 2U B 2R' B' 2U' B 2R B' F2
14 HTM · 10 STM · 16 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R2 2L' U2 2L 2D' 2L' U2 2L 2D R2. Every algorithm above was run by our logic engine from that state and reaches "solved".