MI
Algorithms (3)
2U 2L' U' 2L 2U' 2L' U 2L
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 8 solvers' sheets
U' 2F' U' 2F 2U' 2F' U 2F Uw
14 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
U' B 2U B' 2L B 2U' B' 2L' U
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Uw' 2F' U' 2F 2U 2F' U 2F U. Every algorithm above was run by our logic engine from that state and reaches "solved".