MC
Algorithms (3)
2R 2U' 2R' U 2R 2U 2R' U'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 21 solvers' sheets
4Dw' 2R 2U2 2R' U 2R 2U2 2R' y'
14 HTM · 8 STM · 18 QTM
3-gen
rotation
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
U2 2L 2U 2L' U 2L 2U' 2L' U
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y 2R 2U2 2R' U' 2R 2U2 2R' 4Dw. Every algorithm above was run by our logic engine from that state and reaches "solved".