LJ
Algorithms (3)
2L 2B2 2L' F2 2L 2B2 2L' F2
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
F' 2D 2B' 2D' F2 2D 2B 2D' F'
15 HTM · 9 STM · 16 QTM
3-gen
rotationless
<F,D,B>
One hand: needs L, B, S or E
Cubemuch
3Lw Dw 2R Dw' 2B2 Dw 2R' Dw' 2B2 3Lw'
14 HTM · 10 STM · 18 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F 2D 2B' 2D' F2 2D 2B 2D' F. Every algorithm above was run by our logic engine from that state and reaches "solved".