JT
Algorithms (3)
Uw' 2R2 2U 2R U 2R' 2U' 2R U' 2R Uw
My choice
18 HTM · 11 STM · 20 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 3 solvers' sheets
F' 2R' U' 2L' U 2R U' 2L U F
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F2 2L' U2 2L 2D2 2L' U2 2L 2D2 F2
16 HTM · 10 STM · 24 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' U' 2L' U 2R' U' 2L U 2R F. Every algorithm above was run by our logic engine from that state and reaches "solved".