JI
Algorithms (3)
U' 2L' U 2R U' 2L U 2R'
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
2R' 2U' R 2U 2R 2U' R' 2U
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
2U 2B' U 2F U' 2B U 2F' Uw'
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U' R 2U 2R' 2U' R' 2U 2R. Every algorithm above was run by our logic engine from that state and reaches "solved".