JD
Algorithms (3)
2L' 2U2 2L U2 2L' 2U2 2L U2
My choice
14 HTM · 8 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 9 solvers' sheets
U 2B' 2U' 2B U2 2B' 2U 2B U
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
U' 2F' 2U 2F U2 2F' 2U' 2F U'
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2B' 2U' 2B U2 2B' 2U 2B U'. Every algorithm above was run by our logic engine from that state and reaches "solved".