IV
Algorithms (3)
2R2 U' 2L' U 2R2 U' 2L U
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 8 solvers' sheets
2D 2R2 U' 2L' U 2R2 U' 2L U 2D'
16 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Dw' 2L 3Dw 2R2 3Dw' 2L' 3Dw 2R2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2D U' 2L' U 2R2 U' 2L U 2R2 2D'. Every algorithm above was run by our logic engine from that state and reaches "solved".