HO
Algorithms (3)
L' 2D' 2L U' 2L' 2D2 2L U 2L' 2D' L
My choice
18 HTM · 11 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 5 solvers' sheets
4Fw' D' 2R2 Uw' 2L' Uw 2R2 Uw' 2L Uw D 4Fw
16 HTM · 12 STM · 20 QTM
rotationless
<U,R,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
L' 2D2 Rw' 2U' Rw 2D2 Rw' 2U Rw L
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 4Fw' D' Uw' 2L' Uw 2R2 Uw' 2L Uw 2R2 D 4Fw. Every algorithm above was run by our logic engine from that state and reaches "solved".