GI
Algorithms (3)
2L2 2D' 2L U' 2L' 2D 2L U 2L
My choice
16 HTM · 9 STM · 18 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
L2 2U' 2L' U' 2L 2U 2L' U 2L L2
16 HTM · 10 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
L2 2B 3Lw 2F 3Lw' 2B' 3Lw 2F' 3Lw' L2
14 HTM · 10 STM · 16 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: L2 2L' U' 2L 2U' 2L' U 2L 2U L2. Every algorithm above was run by our logic engine from that state and reaches "solved".