FM
Algorithms (3)
L' 2U' 2L' U' 2L 2U2 2L' U 2L 2U' L
My choice
18 HTM · 11 STM · 20 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
3Lw' R' 2B R 2U2 R' 2B' R 2U2 3Lw
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
L' R' 2B R 2U2 R' 2B' R 2U2 L
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw' 2U2 R' 2B R 2U2 R' 2B' R 3Lw. Every algorithm above was run by our logic engine from that state and reaches "solved".