FA
Algorithms (3)
U 2R' 2U' 2R U' 2R' 2U 2R
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 15 solvers' sheets
2U 2B' 2U 2B U' 2B' 2U' 2B U 2U'
18 HTM · 10 STM · 18 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
2B' 2U2 2B U' 2B' 2U2 2B U
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<U,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U U' 2B' 2U 2B U 2B' 2U' 2B 2U'. Every algorithm above was run by our logic engine from that state and reaches "solved".