EM
Algorithms (3)
2U' 2L' U' 2L 2U2 2L' U 2L 2U'
My choice
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
R' U 2F' U' 2B' U 2F U' 2B R
14 HTM · 10 STM · 14 QTM
rotationless
<U,R,F,B>
One hand: needs L, B, S or E
Cubemuch
2U2 2F' U2 2F 2U2 2F' U2 2F
14 HTM · 8 STM · 20 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: R' 2B' U 2F' U' 2B U 2F U' R. Every algorithm above was run by our logic engine from that state and reaches "solved".