EA
Algorithms (3)
2L 2U' 2L' U' 2L 2U 2L' U
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 17 solvers' sheets
U2 2R 2U 2R' U' 2R 2U' 2R' U'
15 HTM · 9 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
U 3Lw 2F' 3Lw' 2B 3Lw 2F 3Lw' 2B' U'
14 HTM · 10 STM · 14 QTM
rotationless
<U,F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 2R 2U 2R' U 2R 2U' 2R' U2. Every algorithm above was run by our logic engine from that state and reaches "solved".