CE
Algorithms (3)
U 2R 2U 2R' U' 2R 2U' 2R'
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
BLDDB, on 22 solvers' sheets
2B' 2R B' 2R' 2B 2R B 2R'
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<R,B>
One hand: needs L, B, S or E
Cubemuch
3Lw 2F' 3Lw' 2B 3Lw 2F 3Lw' 2B'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R B' 2R' 2B' 2R B 2R' 2B. Every algorithm above was run by our logic engine from that state and reaches "solved".