AD
Algorithms (3)
3Fw' 2B' 2D2 2B U 2B' 2D2 2B U' 3Fw
My choice
16 HTM · 10 STM · 20 QTM
rotationless
<U,F,D,B>
One hand: needs L, B, S or E
Cubemuch
3Lw2 2B2 3Dw 2R2 3Dw' 2B2 3Dw 2R2 3Dw' 3Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
Lw2 2B2 3Dw 2R2 3Dw' 2B2 3Dw 2R2 3Dw' Lw2
14 HTM · 10 STM · 24 QTM
rotationless
<R,D,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw2 3Dw 2R2 3Dw' 2B2 3Dw 2R2 3Dw' 2B2 3Lw2. Every algorithm above was run by our logic engine from that state and reaches "solved".