SA
Algorithms (3)
U2 2R' D2 2R U2 2R' D2 2R
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 14 solvers' sheets
D' U R' 2U R U2 R' 2U' R U D
13 HTM · 11 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 8 solvers' sheets
D' U2 2R' D' 2R U2 2R' D 2R D
14 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 4 solvers' sheets
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D' U' R' 2U R U2 R' 2U' R U' D. Every algorithm above was run by our logic engine from that state and reaches "solved".