XP
Algorithms (3)
2L2 U2 2L 3D' 2L' U2 2L 3D 2L
My choice
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
U 2F' U' 3B2 U 2F U' 3B2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
U 2F' U' 3F2 U 2F U' 3F2
12 HTM · 8 STM · 16 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3B2 U 2F' U' 3B2 U 2F U'. Every algorithm above was run by our logic engine from that state and reaches "solved".