XF
Algorithms (3)
2L2 U2 2L' 3D' 2L U2 2L' 3D 2L'
My choice
16 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
4Dw 2R U' 3L2 U 2R' U' 3L2 y
12 HTM · 8 STM · 16 QTM
rotation
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U 2F U' 3B2 U 2F' U' 3B2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y' 3L2 U 2R U' 3L2 U 2R' 4Dw'. Every algorithm above was run by our logic engine from that state and reaches "solved".