XD
Algorithms (3)
U' D 3L' 2U2 3L U2 3L' 2U2 3L U' D'
My choice
17 HTM · 11 STM · 22 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
y 3L 2U2 3L' U2 3L 2U2 3L' U2 y'
14 HTM · 8 STM · 20 QTM
2-gen
rotation
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3F 2U2 3F' U2 3F 2U2 3F' U2
14 HTM · 8 STM · 20 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y U2 3L 2U2 3L' U2 3L 2U2 3L' y'. Every algorithm above was run by our logic engine from that state and reaches "solved".