WX
Algorithms (3)
3Lw U2 2L U' 3L U 2L' U' 3L' U' 3Lw'
My choice
15 HTM · 11 STM · 16 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U2 2L2 U' 3L2 U 2L2 U' 3L2 U'
13 HTM · 9 STM · 22 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
Cubemuch
3F2 3Dw' 2R2 3Dw 3F2 3Dw' 2R2 3Dw
12 HTM · 8 STM · 20 QTM
3-gen
rotationless
<R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U 3L2 U 2L2 U' 3L2 U 2L2 U2. Every algorithm above was run by our logic engine from that state and reaches "solved".