VX
Algorithms (3)
3F' 2U2 3F D2 3F' 2U2 3F D2
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<U,F,D>
One hand: R, U and M with F and D
Cubemuch
2R2 3Fw2 U2 3Fw2 2R2 3Fw2 U2 3Fw2
10 HTM · 8 STM · 20 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
2R2 Fw2 3Dw2 Fw2 2R2 Fw2 3Dw2 Fw2
10 HTM · 8 STM · 20 QTM
3-gen
rotationless
<R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Fw2 U2 3Fw2 2R2 3Fw2 U2 3Fw2 2R2. Every algorithm above was run by our logic engine from that state and reaches "solved".