TX
Algorithms (3)
D U' 3L2 U 2R' U' 3L2 U 2R D'
My choice
14 HTM · 10 STM · 18 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2L' 3D2 2L' U2 2L 3D2 2L' U2 2L2
16 HTM · 9 STM · 24 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3F2 Dw 2R' Dw' 3F2 Dw 2R Dw'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,F,D>
One hand: R, U and M with F and D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2L2 U2 2L 3D2 2L' U2 2L 3D2 2L. Every algorithm above was run by our logic engine from that state and reaches "solved".