TM
Algorithms (3)
2U U' 3L' U 2R' U' 3L U 2R 2U'
My choice
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
y F' 3D' 2L' U 2L 3D 2L' U' 2L F y'
16 HTM · 10 STM · 16 QTM
rotation
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R 3D' R' 3D 2R' 3D' R 3D
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y F' 2L' U 2L 3D' 2L' U' 2L 3D F y'. Every algorithm above was run by our logic engine from that state and reaches "solved".