TE
Algorithms (3)
Uw' 3L' Uw 2R' Uw' 3L Uw 2R
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
y' F' 3D 2L' U' 2L 3D' 2L' U 2L F y
16 HTM · 10 STM · 16 QTM
rotation
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Uw 3L 3Uw' 2R' 3Uw 3L' 3Uw' 2R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y' F' 2L' U' 2L 3D 2L' U 2L 3D' F y. Every algorithm above was run by our logic engine from that state and reaches "solved".