TA
Algorithms (3)
x' 2R U' 3L' U 2R' U' 3L U x
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotation
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3L U' 3L' U 2R' U' 3L U 3L' 2R
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U' 2L 3D2 2L' U' 2L 3D2 2L' U2
15 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R' 3L U' 3L' U 2R U' 3L U 3L'. Every algorithm above was run by our logic engine from that state and reaches "solved".