SM
Algorithms (3)
3L U' 3L 2U 3L' U 3L 2U' 3L2
My choice
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3Lw U' 3R' 2U 3R U 3R' 2U' 3R 3Lw'
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
R2 3Rw 2F' 3Rw' 3F 3Rw 2F 3Rw' 3F' R2
14 HTM · 10 STM · 16 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw 3R' 2U 3R U' 3R' 2U' 3R U 3Lw'. Every algorithm above was run by our logic engine from that state and reaches "solved".