RJ
Algorithms (3)
2L U2 2L' 3D2 2L U2 2L' 3D2
My choice
14 HTM · 8 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
U' 3D2 2R U 2R' 3D2 2R U' 2R' U
16 HTM · 10 STM · 20 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
B' 2R U 3R' U' 2R' U 3R U' B
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: U' 2R U 2R' 3D2 2R U' 2R' 3D2 U. Every algorithm above was run by our logic engine from that state and reaches "solved".