QX
Algorithms (3)
D2 2R2 U 3L U' 2R2 U 3L' U' D2
My choice
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
2L B 2L' 3F2 2L B' 2L' 3F2
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<F,L,B>
One hand: needs L, B, S or E
Cubemuch
3F2 2R B' 2R' 3F2 2R B 2R'
14 HTM · 8 STM · 18 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3F2 2L B 2L' 3F2 2L B' 2L'. Every algorithm above was run by our logic engine from that state and reaches "solved".