QM
Algorithms (3)
3L U 3L' 2U' 3L U' 3L' 2U
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
2U' R 3F' R' 2U' R 3F R' 2U2
14 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
2U' R' 3F' R 2U' R' 3F R 2U2
14 HTM · 9 STM · 16 QTM
3-gen
rotationless
<U,R,F>
One hand: R, U and M with F or D
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U2 R 3F' R' 2U R 3F R' 2U. Every algorithm above was run by our logic engine from that state and reaches "solved".