PK
Algorithms (3)
3D U 3L' U' 2R' U 3L U' 2R 3D'
My choice
16 HTM · 10 STM · 16 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F 3D' 2L' U2 2L 3D 2L' U2 2L F'
16 HTM · 10 STM · 18 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3Uw 3R U 2L' U' 3R' U 2L U' 3Uw'
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F 2L' U2 2L 3D' 2L' U2 2L 3D F'. Every algorithm above was run by our logic engine from that state and reaches "solved".