OA
Algorithms (3)
3L' 2D 3L U' 3L' 2D' 3L U
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 6 solvers' sheets
R' U 2R' 3D' 2R U' 2R' 3D Rw
14 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
3F R' 2B' R 3F' R' 2B R
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: Rw' 3D' 2R U 2R' 3D 2R U' R. Every algorithm above was run by our logic engine from that state and reaches "solved".