MX
Algorithms (3)
D 3L' 2U 3L' U' 3L 2U' 3L' U 3L2 D'
My choice
18 HTM · 11 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
D' 3R' 2U' 3R' U 3R 2U 3R' U' 3R2 D
18 HTM · 11 STM · 20 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
U2 2L2 Dw' 3F' Dw 2L2 Dw' 3F Dw U2
14 HTM · 10 STM · 20 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D' 3R2 U 3R 2U' 3R' U' 3R 2U 3R D. Every algorithm above was run by our logic engine from that state and reaches "solved".