MK
Algorithms (3)
3L2 2U' 3L U 3L' 2U 3L U' 3L
My choice
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F2 2U 3L' U' 3L 2U' 3L' U 3L F2
16 HTM · 10 STM · 18 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3R2 2U' 3R' U 3R 2U 3R' U' 3R'
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F2 3L' U' 3L 2U 3L' U 3L 2U' F2. Every algorithm above was run by our logic engine from that state and reaches "solved".