MI
Algorithms (3)
2U 3L' U' 3L 2U' 3L' U 3L
My choice
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
2U 3R U' 3R' 2U' 3R U 3R'
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
U' 2U B 3L B' 2U' B 3L' B' U
14 HTM · 10 STM · 14 QTM
3-gen
rotationless
<U,L,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3R U' 3R' 2U 3R U 3R' 2U'. Every algorithm above was run by our logic engine from that state and reaches "solved".