LX
Algorithms (3)
D' U 3L2 U 2L' U' 3L2 U 2L U2 D
My choice
15 HTM · 11 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
3F2 2R' F2 2R 3F2 2R' F2 2R
14 HTM · 8 STM · 20 QTM
2-gen
rotationless
<R,F>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
U 2L U' 3F2 U 2L' U' 3F2
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R' F2 2R 3F2 2R' F2 2R 3F2. Every algorithm above was run by our logic engine from that state and reaches "solved".