LI
Algorithms (3)
U' 3L' U' 2L' U 3L U' 2L U2
My choice
13 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
Cubemuch
F 2U 3F' 2U' F' 2U 3F 2U'
14 HTM · 8 STM · 14 QTM
2-gen
rotationless
<U,F>
One hand: R, U and M with F or D
Cubemuch
2L 3F2 2L' F' 2L 3F2 2L' F
14 HTM · 8 STM · 18 QTM
2-gen
rotationless
<F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2U 3F' 2U' F 2U 3F 2U' F'. Every algorithm above was run by our logic engine from that state and reaches "solved".