KO
Algorithms (3)
3L' U 3L 2D' 3L' U' 3L 2D
My choice
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
3R U 3R' 2D' 3R U' 3R' 2D
14 HTM · 8 STM · 14 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
Cubemuch
3Rw 2F 3Rw' 3B' 3Rw 2F' 3Rw' 3B
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,F,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2D' 3R U 3R' 2D 3R U' 3R'. Every algorithm above was run by our logic engine from that state and reaches "solved".