KJ
Algorithms (3)
2R U 3L' U' 2R' U 3L U'
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2R 3Uw 3L' 3Uw' 2R' 3Uw 3L 3Uw'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
2R Uw 3L' Uw' 2R' Uw 3L Uw'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Uw 3L' 3Uw' 2R 3Uw 3L 3Uw' 2R'. Every algorithm above was run by our logic engine from that state and reaches "solved".