KE
Algorithms (3)
F2 3L' U' 3L 2U' 3L' U 3L 2U F2
My choice
16 HTM · 10 STM · 18 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
4Lw' 3D' 2R' U' 2R 3D 2R' U 3Lw
14 HTM · 9 STM · 14 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
3L' U 3L' 2U 3L U' 3L' 2U' 3L2
16 HTM · 9 STM · 18 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3Lw' U' 2R 3D' 2R' U 2R 3D 4Lw. Every algorithm above was run by our logic engine from that state and reaches "solved".