JW
Algorithms (3)
U 3L2 U' 2R U 3L2 U' 2R'
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
D2 U' 3L2 U 2R U' 3L2 U 2R' D2
14 HTM · 10 STM · 20 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U 3R2 U' 2R U 3R2 U' 2R'
12 HTM · 8 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: D2 2R U' 3L2 U 2R' U' 3L2 U D2. Every algorithm above was run by our logic engine from that state and reaches "solved".