JU
Algorithms (3)
U' 3L2 U 2R U' 3L2 U 2R'
My choice
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 4 solvers' sheets
U' 3R2 U 2R U' 3R2 U 2R'
12 HTM · 8 STM · 16 QTM
2-gen
rotationless
oh
<U,R>
One hand: R and U only
Cubemuch
2R' F' 3L' F 2R F' 3L F
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2R U' 3R2 U 2R' U' 3R2 U. Every algorithm above was run by our logic engine from that state and reaches "solved".