JQ
Algorithms (3)
U 3L U' 2R U 3L' U' 2R'
My choice
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 2 solvers' sheets
F' 3L' U' 3L 2U2 3L' U 3L 2U2 F
16 HTM · 10 STM · 20 QTM
3-gen
rotationless
<U,F,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2R' F 3L2 F' 2R F 3L2 F'
12 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,F,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: F' 2U2 3L' U' 3L 2U2 3L' U 3L F. Every algorithm above was run by our logic engine from that state and reaches "solved".