JO
Algorithms (3)
F 3L' U 3L 2D' 3L' U' 3L 2D F'
My choice
16 HTM · 10 STM · 16 QTM
rotationless
<U,F,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
2D' U 3L' U' 2R U 3L U' 2R' 2D
16 HTM · 10 STM · 16 QTM
rotationless
<U,R,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
S' 2R Uw' 3L' Uw 2R' Uw' 3L Uw S
16 HTM · 10 STM · 16 QTM
rotationless
<U,R,L,S>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 2D' 2R U 3L' U' 2R' U 3L U' 2D. Every algorithm above was run by our logic engine from that state and reaches "solved".