JL
Algorithms (3)
2R' 3D R2 3D' 2R 3D R2 3D'
My choice
14 HTM · 8 STM · 16 QTM
2-gen
rotationless
<R,D>
One hand: R, U and M with F or D
Cubemuch
2R' 3D' 3Lw2 3D 2R 3D' 3Lw2 3D
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
2R' 3D' L2 3D 2R 3D' L2 3D
14 HTM · 8 STM · 16 QTM
3-gen
rotationless
<R,D,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 3D' 3Lw2 3D 2R' 3D' 3Lw2 3D 2R. Every algorithm above was run by our logic engine from that state and reaches "solved".