JF
Algorithms (3)
U' 2R U 2R' 3D 2R U' 2R' 3D' U
My choice
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 2 solvers' sheets
y' 3D' 2R U 2R' 3D 2R U' 2R' y
14 HTM · 8 STM · 14 QTM
3-gen
rotation
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
2R' B 3D B' 2R B 3D' B'
12 HTM · 8 STM · 12 QTM
3-gen
rotationless
<R,D,B>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: y' 2R U 2R' 3D' 2R U' 2R' 3D y. Every algorithm above was run by our logic engine from that state and reaches "solved".