JA
Algorithms (3)
3L' U' 3L U 2R U' 3L' U 3L 2R'
My choice
16 HTM · 10 STM · 16 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
y 2R' 3D 2R U' 2R' 3D' 2R 4Dw
14 HTM · 8 STM · 14 QTM
3-gen
rotation
<U,R,D>
One hand: R, U and M with F or D
BLDDB, on 1 solver's sheet
U' 2L' 3D2 2L U' 2L' 3D2 2L U2
15 HTM · 9 STM · 20 QTM
3-gen
rotationless
<U,D,L>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: 4Dw' 2R' 3D 2R U 2R' 3D' 2R y'. Every algorithm above was run by our logic engine from that state and reaches "solved".