IR
Algorithms (3)
U2 2L U 3L' U' 2L' U 3L U
My choice
13 HTM · 9 STM · 14 QTM
2-gen
rotationless
<U,L>
One hand: needs L, B, S or E
BLDDB, on 3 solvers' sheets
B' 3L' U' 3L 2U2 3L' U 3L 2U2 B
16 HTM · 10 STM · 20 QTM
3-gen
rotationless
<U,L,B>
One hand: needs L, B, S or E
BLDDB, on 1 solver's sheet
U2 2L U 3R U' 2L' U 3R' U
13 HTM · 9 STM · 14 QTM
3-gen
rotationless
<U,R,L>
One hand: needs L, B, S or E
Cubemuch
How this case is verified
The case is the source's setup (or, where it has none, another source algorithm reversed). Setup: B' 2U2 3L' U' 3L 2U2 3L' U 3L B. Every algorithm above was run by our logic engine from that state and reaches "solved".